"email": 예제
*************

다음은 "email" 패키지를 사용하여 간단한 전자 우편 메시지뿐만 아니라 더
복잡한 MIME 메시지를 읽고 쓰고 보내는 방법에 대한 몇 가지 예입니다.

먼저 간단한 텍스트 메시지를 만들고 보내는 방법을 살펴보겠습니다 (텍스
트 내용과 주소에 유니코드 문자가 포함될 수 있습니다):

   # Import smtplib for the actual sending function
   import smtplib

   # Import the email modules we'll need
   from email.message import EmailMessage

   # Open the plain text file whose name is in textfile for reading.
   with open(textfile) as fp:
       # Create a text/plain message
       msg = EmailMessage()
       msg.set_content(fp.read())

   # me == the sender's email address
   # you == the recipient's email address
   msg['Subject'] = f'The contents of {textfile}'
   msg['From'] = me
   msg['To'] = you

   # Send the message via our own SMTP server.
   s = smtplib.SMTP('localhost')
   s.send_message(msg)
   s.quit()

"parser" 모듈의 클래스를 사용하여 **RFC 822** 헤더를 쉽게 구문 분석할
수 있습니다:

   # Import the email modules we'll need
   from email.parser import BytesParser, Parser
   from email.policy import default

   # If the e-mail headers are in a file, uncomment these two lines:
   # with open(messagefile, 'rb') as fp:
   #     headers = BytesParser(policy=default).parse(fp)

   #  Or for parsing headers in a string (this is an uncommon operation), use:
   headers = Parser(policy=default).parsestr(
           'From: Foo Bar <user@example.com>\n'
           'To: <someone_else@example.com>\n'
           'Subject: Test message\n'
           '\n'
           'Body would go here\n')

   #  Now the header items can be accessed as a dictionary:
   print('To: {}'.format(headers['to']))
   print('From: {}'.format(headers['from']))
   print('Subject: {}'.format(headers['subject']))

   # You can also access the parts of the addresses:
   print('Recipient username: {}'.format(headers['to'].addresses[0].username))
   print('Sender name: {}'.format(headers['from'].addresses[0].display_name))

다음은 디렉터리에 있을 수 있는 가족사진을 포함하는 MIME 메시지를 보내
는 방법의 예입니다:

   # Import smtplib for the actual sending function.
   import smtplib

   # Here are the email package modules we'll need.
   from email.message import EmailMessage

   # Create the container email message.
   msg = EmailMessage()
   msg['Subject'] = 'Our family reunion'
   # me == the sender's email address
   # family = the list of all recipients' email addresses
   msg['From'] = me
   msg['To'] = ', '.join(family)
   msg.preamble = 'You will not see this in a MIME-aware mail reader.\n'

   # Open the files in binary mode.  You can also omit the subtype
   # if you want MIMEImage to guess it.
   for file in pngfiles:
       with open(file, 'rb') as fp:
           img_data = fp.read()
       msg.add_attachment(img_data, maintype='image',
                                    subtype='png')

   # Send the email via our own SMTP server.
   with smtplib.SMTP('localhost') as s:
       s.send_message(msg)

다음은 디렉터리의 전체 내용을 전자 우편 메시지로 보내는 방법의 예입니
다: [1]

   #!/usr/bin/env python3

   """Send the contents of a directory as a MIME message."""

   import os
   import smtplib
   # For guessing MIME type based on file name extension
   import mimetypes

   from argparse import ArgumentParser

   from email.message import EmailMessage
   from email.policy import SMTP


   def main():
       parser = ArgumentParser(description="""\
   Send the contents of a directory as a MIME message.
   Unless the -o option is given, the email is sent by forwarding to your local
   SMTP server, which then does the normal delivery process.  Your local machine
   must be running an SMTP server.
   """)
       parser.add_argument('-d', '--directory',
                           help="""Mail the contents of the specified directory,
                           otherwise use the current directory.  Only the regular
                           files in the directory are sent, and we don't recurse to
                           subdirectories.""")
       parser.add_argument('-o', '--output',
                           metavar='FILE',
                           help="""Print the composed message to FILE instead of
                           sending the message to the SMTP server.""")
       parser.add_argument('-s', '--sender', required=True,
                           help='The value of the From: header (required)')
       parser.add_argument('-r', '--recipient', required=True,
                           action='append', metavar='RECIPIENT',
                           default=[], dest='recipients',
                           help='A To: header value (at least one required)')
       args = parser.parse_args()
       directory = args.directory
       if not directory:
           directory = '.'
       # Create the message
       msg = EmailMessage()
       msg['Subject'] = f'Contents of directory {os.path.abspath(directory)}'
       msg['To'] = ', '.join(args.recipients)
       msg['From'] = args.sender
       msg.preamble = 'You will not see this in a MIME-aware mail reader.\n'

       for filename in os.listdir(directory):
           path = os.path.join(directory, filename)
           if not os.path.isfile(path):
               continue
           # Guess the content type based on the file's extension.  Encoding
           # will be ignored, although we should check for simple things like
           # gzip'd or compressed files.
           ctype, encoding = mimetypes.guess_type(path)
           if ctype is None or encoding is not None:
               # No guess could be made, or the file is encoded (compressed), so
               # use a generic bag-of-bits type.
               ctype = 'application/octet-stream'
           maintype, subtype = ctype.split('/', 1)
           with open(path, 'rb') as fp:
               msg.add_attachment(fp.read(),
                                  maintype=maintype,
                                  subtype=subtype,
                                  filename=filename)
       # Now send or store the message
       if args.output:
           with open(args.output, 'wb') as fp:
               fp.write(msg.as_bytes(policy=SMTP))
       else:
           with smtplib.SMTP('localhost') as s:
               s.send_message(msg)


   if __name__ == '__main__':
       main()

다음은 위와 같은 MIME 메시지를 디렉터리로 푸는 방법의 예입니다:

   #!/usr/bin/env python3

   """Unpack a MIME message into a directory of files."""

   import os
   import email
   import mimetypes

   from email.policy import default

   from argparse import ArgumentParser


   def main():
       parser = ArgumentParser(description="""\
   Unpack a MIME message into a directory of files.
   """)
       parser.add_argument('-d', '--directory', required=True,
                           help="""Unpack the MIME message into the named
                           directory, which will be created if it doesn't already
                           exist.""")
       parser.add_argument('msgfile')
       args = parser.parse_args()

       with open(args.msgfile, 'rb') as fp:
           msg = email.message_from_binary_file(fp, policy=default)

       try:
           os.mkdir(args.directory)
       except FileExistsError:
           pass

       counter = 1
       for part in msg.walk():
           # multipart/* are just containers
           if part.get_content_maintype() == 'multipart':
               continue
           # Applications should really sanitize the given filename so that an
           # email message can't be used to overwrite important files
           filename = part.get_filename()
           if not filename:
               ext = mimetypes.guess_extension(part.get_content_type())
               if not ext:
                   # Use a generic bag-of-bits extension
                   ext = '.bin'
               filename = f'part-{counter:03d}{ext}'
           counter += 1
           with open(os.path.join(args.directory, filename), 'wb') as fp:
               fp.write(part.get_payload(decode=True))


   if __name__ == '__main__':
       main()

다음은 대체 일반 텍스트 버전으로 HTML 메시지를 만드는 방법의 예입니다.
좀 더 흥미롭게 하기 위해, html 부분에 관련 이미지를 포함하고, 보낼 뿐
만 아니라, 보낼 것의 사본을 디스크에 저장합니다.

   #!/usr/bin/env python3

   import smtplib

   from email.message import EmailMessage
   from email.headerregistry import Address
   from email.utils import make_msgid

   # Create the base text message.
   msg = EmailMessage()
   msg['Subject'] = "Ayons asperges pour le déjeuner"
   msg['From'] = Address("Pepé Le Pew", "pepe", "example.com")
   msg['To'] = (Address("Penelope Pussycat", "penelope", "example.com"),
                Address("Fabrette Pussycat", "fabrette", "example.com"))
   msg.set_content("""\
   Salut!

   Cela ressemble à un excellent recipie[1] déjeuner.

   [1] http://www.yummly.com/recipe/Roasted-Asparagus-Epicurious-203718

   --Pepé
   """)

   # Add the html version.  This converts the message into a multipart/alternative
   # container, with the original text message as the first part and the new html
   # message as the second part.
   asparagus_cid = make_msgid()
   msg.add_alternative("""\
   <html>
     <head></head>
     <body>
       <p>Salut!</p>
       <p>Cela ressemble à un excellent
           <a href="http://www.yummly.com/recipe/Roasted-Asparagus-Epicurious-203718">
               recipie
           </a> déjeuner.
       </p>
       <img src="cid:{asparagus_cid}" />
     </body>
   </html>
   """.format(asparagus_cid=asparagus_cid[1:-1]), subtype='html')
   # note that we needed to peel the <> off the msgid for use in the html.

   # Now add the related image to the html part.
   with open("roasted-asparagus.jpg", 'rb') as img:
       msg.get_payload()[1].add_related(img.read(), 'image', 'jpeg',
                                        cid=asparagus_cid)

   # Make a local copy of what we are going to send.
   with open('outgoing.msg', 'wb') as f:
       f.write(bytes(msg))

   # Send the message via local SMTP server.
   with smtplib.SMTP('localhost') as s:
       s.send_message(msg)

마지막 예에서 메시지를 보냈다면, 다음은 그것을 처리하는 한 가지 방법입
니다:

   import os
   import sys
   import tempfile
   import mimetypes
   import webbrowser

   # Import the email modules we'll need
   from email import policy
   from email.parser import BytesParser


   def magic_html_parser(html_text, partfiles):
       """Return safety-sanitized html linked to partfiles.

       Rewrite the href="cid:...." attributes to point to the filenames in partfiles.
       Though not trivial, this should be possible using html.parser.
       """
       raise NotImplementedError("Add the magic needed")


   # In a real program you'd get the filename from the arguments.
   with open('outgoing.msg', 'rb') as fp:
       msg = BytesParser(policy=policy.default).parse(fp)

   # Now the header items can be accessed as a dictionary, and any non-ASCII will
   # be converted to unicode:
   print('To:', msg['to'])
   print('From:', msg['from'])
   print('Subject:', msg['subject'])

   # If we want to print a preview of the message content, we can extract whatever
   # the least formatted payload is and print the first three lines.  Of course,
   # if the message has no plain text part printing the first three lines of html
   # is probably useless, but this is just a conceptual example.
   simplest = msg.get_body(preferencelist=('plain', 'html'))
   print()
   print(''.join(simplest.get_content().splitlines(keepends=True)[:3]))

   ans = input("View full message?")
   if ans.lower()[0] == 'n':
       sys.exit()

   # We can extract the richest alternative in order to display it:
   richest = msg.get_body()
   partfiles = {}
   if richest['content-type'].maintype == 'text':
       if richest['content-type'].subtype == 'plain':
           for line in richest.get_content().splitlines():
               print(line)
           sys.exit()
       elif richest['content-type'].subtype == 'html':
           body = richest
       else:
           print("Don't know how to display {}".format(richest.get_content_type()))
           sys.exit()
   elif richest['content-type'].content_type == 'multipart/related':
       body = richest.get_body(preferencelist=('html'))
       for part in richest.iter_attachments():
           fn = part.get_filename()
           if fn:
               extension = os.path.splitext(part.get_filename())[1]
           else:
               extension = mimetypes.guess_extension(part.get_content_type())
           with tempfile.NamedTemporaryFile(suffix=extension, delete=False) as f:
               f.write(part.get_content())
               # again strip the <> to go from email form of cid to html form.
               partfiles[part['content-id'][1:-1]] = f.name
   else:
       print("Don't know how to display {}".format(richest.get_content_type()))
       sys.exit()
   with tempfile.NamedTemporaryFile(mode='w', delete=False) as f:
       f.write(magic_html_parser(body.get_content(), partfiles))
   webbrowser.open(f.name)
   os.remove(f.name)
   for fn in partfiles.values():
       os.remove(fn)

   # Of course, there are lots of email messages that could break this simple
   # minded program, but it will handle the most common ones.

프롬프트까지, 위의 출력은 다음과 같습니다:

   To: Penelope Pussycat <penelope@example.com>, Fabrette Pussycat <fabrette@example.com>
   From: Pepé Le Pew <pepe@example.com>
   Subject: Ayons asperges pour le déjeuner

   Salut!

   Cela ressemble à un excellent recipie[1] déjeuner.

-[ 각주 ]-

[1] 영감과 예를 주신 Matthew Dixon Cowles에게 감사드립니다.
